LENOVO笔试题

1．设计函数 int atoi(char *s)。
int atoi(char *s)
{
     char sign;
     char sign_val = 1;
     int val = 0;
     int n = 0;
     /* skip spaces */
     while (isspace(*s))
         ++s;
     if (*s == '-' || *s == '+')
         /* skip '-' and '+' sign */
     {
         sign = *s;
         if (sign == '-')
             sign_val = -1;
         ++s;
     }
     /* when goes here, it is not space or sign */
     while ((*s != '') && isdigit(*s))
     {
         val = 10 * n + (*s - '0');
         n = val;
         s++;
     }
     if (*s != '')
     {
         printf("non digit in your input!!n");
         exit(-1);
     }
     /* non error occured */
     return (sign_val * val);
}
2．int i=(j=4,k=8,l=16,m=32); printf("%d", i); 输出是多少？
结果为: 32.